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प्रश्न
Which of the following is a quadratic equation?
विकल्प
`x^2 - 2sqrt(x) + 7 = 0`
2x2 – 5x = (x – 1)2
`x - 1/x = 2x^2`
`x^2 + 1/x^2 = 2`
MCQ
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उत्तर
2x2 – 5x = (x – 1)2
Explanation:
A quadratic equation is a polynomial equation of degree 2 (form ax2 + bx + c = 0, a ≠ 0).
- `x^2 - 2sqrt(x) + 7 = 0` contains `sqrt(x)(x^(1/2))`, not a polynomial in x → not quadratic.
- 2x2 – 5x = (x – 1) ⇒ 2x2 – 6x + 1 = 0, a polynomial of degree 2 ⇒ quadratic.
- `x - 1/x = 2x^2` ⇒ multiplying by x gives 2x3 – x2 + 1 = 0, degree 3 ⇒ not quadratic.
- `x^2 + 1/x^2 = 2` ⇒ multiplying by x2 gives x4 – 2x2 + 1 = 0, degree 4 (quartic) ⇒ not quadratic (though it is quadratic in y = x2).
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