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प्रश्न
Which inverse functions have denominator \[\sqrt{1-x^2}\] in their derivatives?
विकल्प
\[\sin^{-1}x\] and \[\cos^{-1}x\]
\[\tan^{-1}x\] and \[\cot^{-1}x\]
\[\sec^{-1}x\] and \[\operatorname{cosec}^{-1}x\]
\[\sin^{-1}x\] and \[\tan^{-1}x\]
MCQ
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उत्तर
Both \[\sin^{-1}x\] and \[\cos^{-1}x\] have denominator \[\sqrt{1-x^2}\]. Their derivatives differ in sign.
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