Question

Which equation follows from \[(1-x^2)\cdot2y_{1}y_{2}+y_{1}^{2}(0-2x)=0\]?

विकल्प

• \[(1-x^2)y_{2}+xy_{1}=0\]

• \[(1-x^2)y_{2}-xy_{1}=0\]

• \[(1-x^2)y_{2}-xy_{1}=1\]

• \[(1-x^2)y_{1}-xy_{2}=0\]

Answer 1

Factoring \[2y_{1}\] from the differentiated expression yields \[2y_{1}((1-x^2)y_{2}-xy_{1})=0\]. Thus the resulting equation is \[(1-x^2)y_{2}-xy_{1}=0\].