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प्रश्न
Which derivative and condition are correct for \[\cot^{-1}x\]?
विकल्प
\[\frac{d}{dx}(\cot^{-1}x)=\frac{1}{1+x^2},\quad x\in\mathbb{R}\]
\[\frac{d}{dx}(\cot^{-1}x)=-\frac{1}{|x|\sqrt{x^2-1}},\quad |x|>1\]
\[\frac{d}{dx}(\cot^{-1}x)=-\frac{1}{\sqrt{1-x^2}},\quad |x|<1\]
\[\frac{d}{dx}(\cot^{-1}x)=-\frac{1}{1+x^2},\quad x\in\mathbb{R}\]
MCQ
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उत्तर
For \[\cot^{-1}x\], the denominator is \[1+x^2\]. A negative sign is especially important, while \[x\in\mathbb{R}\].
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