Advertisements
Advertisements
प्रश्न
What least number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?
Advertisements
उत्तर
Let the number added be x.
∴ (6 + x) : (15 + x) :: (20 + x) : (43 + x)
`=> (6 + x)/(15 + x) = (20 + x)/(43 + x)`
`=>` (6 + x)(43 + x) = (15 + x)(20 + x)
`=>` 258 + 6x + 43x + x2 = 300 + 15x + 20x + x2
`=>` 49x – 35x = 300 – 258
`=>` 14x = 42
`=>` x = 3
Thus, the required number which should be added is 3.
APPEARS IN
संबंधित प्रश्न
If x2, 4 and 9 are in continued proportion, find x.
Using properties of proportion, solve for x:
`(sqrt(x + 5) + sqrt(x - 16))/(sqrt(x + 5) - sqrt(x - 16)) = 7/3`
If p, q and r in continued proportion, then prove the following :
`"p"^2 - "q"^2 + "r"^2 = "q"^4 (1/"p"^2 - 1/"q"^2 - 1/"r"^2)`
Find the mean proportion of: `(1)/(12) and (1)/(75)`
If x + 5 is the mean proportion between x + 2 and x + 9, find the value of x.
Determine if the following ratio form a proportion:
200 mL : 2.5 L and Rs 4 : Rs 50
If the cost of a dozen soaps is Rs 285.60, what will be the cost of 15 such soaps?
If 48 boxes contain 6000 pens, how many such boxes will be needed for 1875 pens?
If `x/a = y/b = z/c`, prove that `[(a^2x^2 + b^2y^2 + c^2z^2)/(a^2x + b^3y +c^3z)]^3 = "xyz"/"abc"`
Determine if the following are in proportion.
4, 6, 8, 12
