Question

What is the peak EMF of the rotating coil?

विकल्प

• \[\varepsilon_0=BA\omega/N\]

• \[\varepsilon_0=NBA\omega\]

• \[\varepsilon_0=NBA\cos(\omega t)\]

• \[\varepsilon_0=NBA/\omega\]

Answer 1

The greatest magnitude of \[\sin(\omega t)\] is one. The amplitude of \[\varepsilon=NBA\omega\sin(\omega t)\] is therefore \[\varepsilon_0=NBA\omega\].