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What is the Angle Between Vectors → a and → B with Magnitudes 2 and √ 3 Respectively? Given → a . → B = √ 3 . - Mathematics

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प्रश्न

What is the angle between vectors \[\vec{a} \text{ and } \vec{b}\] with magnitudes 2 and \[\sqrt{3}\] respectively? Given \[\vec{a} . \vec{b} = \sqrt{3} .\]

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उत्तर

\[\text{ Let } \theta \text{ be the angle between } \vec{a} \text{ and } \vec{b} .\]

\[\text{ Given that }\]

\[\left| \vec{a} \right| = 2, \left| \vec{b} \right| = \sqrt{3} \text{ and } \vec{a} . \vec{b} = \sqrt{3}\]

\[\text{ We know that }\]

\[ \vec{a} . \vec{b} = \left| \vec{a} \right| \left| \vec{b} \right| \cos \theta\]

\[ \Rightarrow \sqrt{3} = \left( 2 \right)\left( \sqrt{3} \right) \cos \theta\]

\[ \Rightarrow \cos \theta = \frac{\sqrt{3}}{2\sqrt{3}}\]

\[ \Rightarrow \cos \theta = \frac{1}{2}\]

\[ \Rightarrow \theta = \cos^{- 1} \left( \frac{1}{2} \right) = \frac{\pi}{3}\]

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अध्याय 24: Scalar Or Dot Product - very short answer [पृष्ठ ४६]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 24 Scalar Or Dot Product
very short answer | Q 1 | पृष्ठ ४६

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