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प्रश्न
Verify whether the following sequence is G.P. If so, find tn.
`sqrt(5), 1/sqrt(5), 1/(5sqrt(5)), 1/(25sqrt(5)), ...`
योग
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उत्तर
`sqrt(5), 1/sqrt(5), 1/(5sqrt(5)), 1/(25sqrt(5)), ...`
t1 = `sqrt(5)`, t2 = `1/sqrt(5)`, t3 = `1/(5sqrt(5))`, t4 = `1/(25sqrt(5)`, ...
Here, `t_2/t_1 = t_3/t_2 = t_4/t_3 = 1/5`
Since, the ratio of any two consecutive terms is a constant, the given sequence is a geometric progression.
Here, a = `sqrt(5)`, r = `1/5`
tn = arn–1
∴ tn = `sqrt(5) (1/5)^(n - 1)`
= `(5)^(1/2) (5)^(1 - n)`
= `(5)^(3/2 - n)`
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