Advertisements
Advertisements
प्रश्न
Verify the distributive property a × (b + c) = (a × b) + (a × c) for the rational numbers a = `(-1)/2`, b = `2/3` and c = `(-5)/6`
Advertisements
उत्तर
Given the rational number a = `(-1)/2`, b = `2/3` and c = `(-5)/6`
a × (b + c) = `(-1)/2 xx (2/3 + ((-5)/6))`
= `(-1)/2 xx (((2 xx 2) + (-5 xx 1))/6)`
= `(-1)/2 xx ((4 + (-5))/6)`
= `(-1)/2 xx ((-1)/6)`
a × (b + c) = `1/12` ...(1)
(a × b) + (a × c) = `((-1)/2 xx 2/3) + ((-1)/2 xx ((-5)/6))`
= `(-2)/6 + 5/12`
= `((-2 xx 2) + 5 xx 1)/12`
= `(-4 + 5)/12`
(a × b) + (a × c) = `1/12` ...(2)
From (1) and (2) we have a × (b + c) = (a × b) + (a × c) is true
Hence multiplication is distributive over addition for rational numbers Q.
APPEARS IN
संबंधित प्रश्न
Write five rational numbers greater than − 2
Verify the property: x × (y × z) = (x × y) × z by taking:
Verify the property: x × (y + z) = x × y + x × z by taking:
Use the distributivity of multiplication of rational numbers over their addition to simplify:
Use the distributivity of multiplication of rational numbers over their addition to simplify:
By what number should we multiply \[\frac{- 1}{6}\] so that the product may be \[\frac{- 23}{9}?\]
`1/5 xx [2/7 + 3/8] = [1/5 xx 2/7] +` ______.
Verify the property x + y = y + x of rational numbers by taking
`x = (-2)/5, y = (-9)/10`
Verify the property x × (y + z) = x × y + x × z of rational numbers by taking.
`x = (-1)/2, y = 2/3, z = 3/4`
Verify the property x × (y + z) = x × y + x × z of rational numbers by taking.
`x = (-2)/3, y = (-4)/6, z = (-7)/9`
