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Vehicles pass through a junction on a busy road at an average rate of 300 per hour. What is the expected number passing in two minutes?

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प्रश्न

Vehicles pass through a junction on a busy road at an average rate of 300 per hour. What is the expected number passing in two minutes?

योग
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उत्तर

In a poisson distribution

Average per hour = 300 vehicles

Mean per minute = `300/60` = 5

∴ λ = 5

P(X = 2) = `("e"^-5 (5)^2)/(2!)`

= `(("e"^-5(25))/2)`

= = e–5(12.5)

= 0.0067379 × 12.5

= 0.08422375

= 0.08422375 × 102 

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अध्याय 7: Probability Distributions - Miscellaneous problems [पृष्ठ १७१]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 7 Probability Distributions
Miscellaneous problems | Q 4. (ii) | पृष्ठ १७१

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