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The distribution of the number of road accidents per day in a city is poisson with mean 4. Find the number of days out of 100 days when there will be no accident

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प्रश्न

The distribution of the number of road accidents per day in a city is poisson with mean 4. Find the number of days out of 100 days when there will be no accident

योग
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उत्तर

In a possion distribution

Mean λ = 4

n = 100

x follows possion distribution with

P(x) = `("e"^(-lambda) lamda^x)/(x!)`

= `("e"^-4 (4)^x)/(x!)`

P(no accident) = P(x = 0)

= `("e"^-4(4)^0)/(0!)`

= `"e"^-4`

= 0.0183

Out of 100 days there will be no accident

= n × P(X = 0)

= 100 × 0.0183

= 1.83

= 2 days  .......(approximately)

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अध्याय 7: Probability Distributions - Exercise 7.2 [पृष्ठ १६०]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 7 Probability Distributions
Exercise 7.2 | Q 10. (i) | पृष्ठ १६०

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