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If the heights of 500 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches , how many students have height between 65 and 71 inches

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प्रश्न

If the heights of 500 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many students have height between 65 and 71 inches

योग
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उत्तर

Let x denote the height of a student N = 500; m = 68.0 inches and σ = 3.0 inches the standard normal variate

z = `(x - mu)/sigma = (x - 68)/3`

P(Between 65 and 71 inches)

P(65 ≤ x ≤ 71)

When x = 65

z = `(65 - 68)/3 = (-3)/3 = - 1`

When x = 71

z = `(71 - 68)/3 = 3/3` = 1

P(65 ≤ x ≤ 71) = P(– 1 < z < 1)

= P(– 1 < z < 0) + P(0 < z < 1)

= P(0 < z < 1) + P(0 < z < 1)

= 2 × [P(0 < z < 1)]

= 2 × 0.3413

= 0.6826

∴ Number of students whose height between 65 and 7 inches

= 0.6826 × 500

= 341.3

= 342  .......(approximately)

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Probability Distributions - Exercise 7.3 [पृष्ठ १६८]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 7 Probability Distributions
Exercise 7.3 | Q 8. (c) | पृष्ठ १६८

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