Advertisements
Advertisements
प्रश्न
Veena has some beads. She wants to make necklaces with an equal number of beads in each. If she makes necklaces of 16 or 24 or 40 beads, there is no bead left over. What is the least number of beads with her?
Advertisements
उत्तर
Veena wants to make necklaces with an equal number of beads in each such there is no bead left over, so the number of beads with her must be in multiples of 16, 24, and 40. Therefore, the least number of beads with her is the LCM of 16, 24, and 40.
Multiples of 16: 16, 32, 48, 64, 80, 96, 112, 128, 144, 160, 176, 192, 208, 224, 240, 256, 272, 288,...
Multiples of 24: 24, 48, 72, 96, 120, 144, 168, 192, 216, 240, 264,...
Multiples of 40: 40, 80, 120, 160, 200, 240, 280,...
Common multiples of 16, 24, and 40: 240,...
∴ Least number of beads with Veena = LCM of 16, 24 and 40 = 240
Thus, the least number of beads with Veena is 240.
संबंधित प्रश्न
Given the fractions `13/45` and `22/75`. write their equivalent fractions with the same denominators and add the fractions.
Find the HCF and LCM:
32, 16
Find the LCM of the numbers given below:
42, 63
Find the least number which when divided by 16, 36, and 40 leaves 5 as the remainder in each case.
Add: `17/28 + 11/35`
Find the LCM set of numbers using prime factorisation method.
14, 42
The number divisible by 5 with no remainder
Find the LCM of the following numbers in which one number is the factor of the other.
- 5, 20
- 6, 18
- 12, 48
- 9, 45
What do you observe in the results obtained?
The least common multiple of two or more numbers is defined as:
The LCM of 2 and 5 is:
