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Vectors → a and → b | → a | = √ 3 , ∣ ∣ → b ∣ ∣ = 2 3 and ( → a × → b ) is a unit vector. Write the angle between → a and → b . - Mathematics

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प्रश्न

Vectors  \[\vec{a} \text{ and }  \vec{b}\] \[\left| \vec{a} \right| = \sqrt{3}, \left| \vec{b} \right| = \frac{2}{3}\text{ and } \left( \vec{a} \times \vec{b} \right)\]  is a unit vector. Write the angle between \[\vec{a} \text{ and } \vec{b}\] .

 

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उत्तर

\[\text{ Given } : \vec{a} \times \vec{b} \text{ is a unit vector } .\]
\[ \Rightarrow \left| \vec{a} \times \vec{b} \right| = 1 . . . (1)\]
\[\text{ Let} \theta \text{ be the angle between } \vec{a} \text{ and } \vec{b} . \]
\[\text{ We know } \]
\[\left| \vec{a} \times \vec{b} \right| = \left| \vec{a} \right| \left| \vec{b} \right| \sin \theta\]
\[\text{ From (1), we get} \]
\[1 = \left( \sqrt{3} \right) \left( \frac{2}{3} \right) \sin \theta \]
\[ \Rightarrow \sin \theta = \frac{\sqrt{3}}{2}\]
\[ \Rightarrow \theta = \frac{\pi}{3}\]

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अध्याय 25: Vector or Cross Product - very short answers [पृष्ठ ३४]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 25 Vector or Cross Product
very short answers | Q 25 | पृष्ठ ३४

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