हिंदी

Using the structural formula, identify the functional group by circling it: Propanone

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प्रश्न

Using the structural formula, identify the functional group by circling it:

Propanone 

रासायनिक समीकरण/संरचनाएँ
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उत्तर

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 17: Carboxylic Acids - Exercise 9 [पृष्ठ २९८]

APPEARS IN

फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 17 Carboxylic Acids
Exercise 9 | Q 4.2 | पृष्ठ २९८
एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 12 Organic Chemistry
MISCELLANEOUS | Q (b) (ii) | पृष्ठ २१९

संबंधित प्रश्न

Draw the structural formula for the acetone compound. What compound is used to describe this compound taken together?


Name the alkyl radical and the functional group of the following organic compound:

CH3OH


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Ethanol, ethane, methane, ethyne and ethene
From the above list, name a compound:

Formed by the dehydration of ethanol by concentrated sulphuric acid.


Name a reagant which can be used to distinguish between ethane and ethene.


Write the equation for the preparation of carbon tetrachloride from methane.


Name the following:

The property of elements by virtue of which atoms of the element can link to each other in the form of a long chain or ring structure.


Write a balanced chemical equation for the following:

Action of water on calcium carbide


Identify the term or substance based on the descriptions given below:

The property by virtue of which the compound has the same molecular formula but different structural formulae.


Name the compound prepared by the following reaction:

\[\ce{C2H5Br + KOH (alcoholic solution) ->}\]


Give the IUPAC name of the organic compound represented by the structural formula given below:

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{Cl}\phantom{..}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{Cl}\phantom{..}\ce{H}\phantom{...}\ce{H}\end{array}\]


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