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Using suitable identity, evaluate the following: 101 × 102 - Mathematics

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प्रश्न

Using suitable identity, evaluate the following:

101 × 102

मूल्यांकन
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उत्तर

101 × 102 = (100 + 1)(100 + 2)

= (100)2 + 100(1 + 2) + 1 × 2  ...[Using identity, (x + a)(x + b) = x2 + x(a + b) + ab]

= 10000 + 300 + 2

= 10302

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अध्याय 2: Polynomials - Exercise 2.3 [पृष्ठ २१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 2 Polynomials
Exercise 2.3 | Q 25. (ii) | पृष्ठ २१

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