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प्रश्न
Using prime factorisation, find which of the following are perfect cubes.
729
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उत्तर
We have, 729 = 3 × 3 × 3 × 3 × 3 × 3
Since, the prime factors appear in triplets.
So, 729 is a perfect cube.
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संबंधित प्रश्न
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\[\sqrt[3]{8 \times . . .} = 8\]
\[\sqrt[3]{} . . . = \sqrt[3]{7} \times \sqrt[3]{8}\]
\[\sqrt[3]{\frac{729}{1331}} = \frac{9}{. . .}\]
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