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Using factor theorem, factorise the following: [2x^{3} + 3x^{2} – 9x – 10]

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प्रश्न

Using factor theorem, factorise the following:

\[2x^{3} + 3x^{2} - 9x - 10\]

योग
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उत्तर

Let $$f(x) = 2x^3 + 3x^2 - 9x - 10$$. 

Since $$f(2) = 16 + 12 - 18 - 10 = 0$$, $$(x - 2)$$ is a factor. 

Dividing $$f(x)$$ by $$(x - 2)$$ gives $$2x^2 + 7x + 5$$. 

Hence, $$2x^3 + 3x^2 - 9x - 10$$

$$= (x - 2)(2x^2 + 7x + 5)$$

$$= (x - 2)(2x + 5)(x + 1)$$

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अध्याय 8: Remainder Theorem and Factor Theorem - EXERCISE 8B [पृष्ठ १२७]

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आर.एस. अग्रवाल Mathematics [English] Class 10 ICSE
अध्याय 8 Remainder Theorem and Factor Theorem
EXERCISE 8B | Q 18. | पृष्ठ १२७
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