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प्रश्न
Using factor theorem, factorise the following:
\[2x^{3} + 3x^{2} - 9x - 10\]
योग
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उत्तर
Let $$f(x) = 2x^3 + 3x^2 - 9x - 10$$.
Since $$f(2) = 16 + 12 - 18 - 10 = 0$$, $$(x - 2)$$ is a factor.
Dividing $$f(x)$$ by $$(x - 2)$$ gives $$2x^2 + 7x + 5$$.
Hence, $$2x^3 + 3x^2 - 9x - 10$$
$$= (x - 2)(2x^2 + 7x + 5)$$
$$= (x - 2)(2x + 5)(x + 1)$$
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