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प्रश्न
Using Euclid’s algorithm, find the HCF of 272 and 1032.
योग
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उत्तर
Since, 1032 > 272
On applying Euclid’s division algorithm, we get
1032 = 272 × 3 + 216
272 = 216 × 1 + 56
216 = 56 × 3 + 48
56 = 48 × 1 + 8
48 = 8 × 6 + 0
Since, remainder comes to be 0.
Hence, the HCF is same as divisor, which is 8.
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