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प्रश्न
Using division of polynomials, state whether
x + 6 is a factor of x2 − x − 42
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उत्तर
Remainder is zero. Hence (x+6) is a factor of x2 -x-42
संबंधित प्रश्न
Divide the given polynomial by the given monomial.
(p3q6 − p6q3) ÷ p3q3
Simplify:\[\frac{16 m^3 y^2}{4 m^2 y}\]
Divide\[\sqrt{3} a^4 + 2\sqrt{3} a^3 + 3 a^2 - 6a\ \text{by}\ 3a\]
Divide 4z3 + 6z2 − z by −\[\frac{1}{2}\]
Divide 3x3y2 + 2x2y + 15xy by 3xy.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 34x − 22x3 − 12x4 − 10x2 − 75 | 3x + 7 |
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 15y4 − 16y3 + 9y2 −\[\frac{10}{3}\] y+6 | 3y − 2 |
Find whether the first polynomial is a factor of the second.
4x2 − 5, 4x4 + 7x2 + 15
Divide 27y3 by 3y
The denominator of a fraction exceeds Its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, we get `3/2`. Find the original fraction.
