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प्रश्न
Use the real number line to find the range of values of x for which:
–1 < x ≤ 6 and –2 ≤ x ≤ 3
योग
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उत्तर
–1 < x ≤ 6 and –2 ≤ x ≤ 3
Both the given in equations are true in the range where their graphs on the real number lines overlap.
The graphs of the given in equations can be drawn as:
–1 < x ≤ 6
–2 < x ≤ 3
From both graphs, it is clear that their common range is –1 < x ≤ 3
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