Question

Use quadratic formula to solve:

`3y + 5/(16y) = 2`

Answer 1

`3y + 5/(16y) = 2`

`(48y^2 + 5)/(16y) = 2`

48y² + 5 = 32y

48y² − 32y + 5 = 0

Comparing 48y² − 32y + 5 = 0 with ax² + bx + c = 0 we get,

a = 48, b = −32 and c = 5.

We know that,

x = `(−b ± sqrt(b^2−4ac))/(2a)`

Substituting values of a, b and c in above equation we get,

x = `(- (-32) ± sqrt((-32)^2−4(48)(5)))/(2(48))`

= `(32 +- sqrt(1024 - 960))/96`

= `(32 +- sqrt64)/96`

= `(32 +- 8)/96`

= `(32 + 8)/96` or `(32 - 8)/96`

= `40/96 or 24/96`

= `5/12 or 1/4`