Advertisements
Advertisements
प्रश्न
Use an expansion formula to find the value.
(1005)2
योग
Advertisements
उत्तर
It is known that (a + b)2 = a2 + 2ab + b2 and (a − b)2 = a2 − 2ab + b2
(1005)2
= (1000 + 5)2
= (1000)2 + 2 × 1000 × 5 + (5)2
= 1000000 + 10000 + 25
= 1010025
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Use a suitable identity to get the following products.
(6x − 7) (6x + 7)
Simplify (4m + 5n)2 + (5m + 4n)2
Using identities, evaluate 1022
Expand (ax + by)2
Which of the options given below is the square of the binomial `(8-1/"x")`?
Factorise the following expressions
x2 + 14x + 49
Factors of 9x2 + 6xy are
Evaluate the following, using suitable identity
1032
The difference of the squares of two consecutive numbers is their sum.
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 6x + 9
