Advertisements
Advertisements
प्रश्न
Use an expansion formula to find the value.
(1005)2
योग
Advertisements
उत्तर
It is known that (a + b)2 = a2 + 2ab + b2 and (a − b)2 = a2 − 2ab + b2
(1005)2
= (1000 + 5)2
= (1000)2 + 2 × 1000 × 5 + (5)2
= 1000000 + 10000 + 25
= 1010025
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify (7m − 8n)2 + (7m + 8n)2
Using a2 − b2 = (a + b) (a − b), find 1532 − 1472
Expand:
`("p"/3 + "q"/4)^2`
Expand (3m + 5)2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 12x + 36
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abx + b2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abxy + b2y2
Factorise the following.
x2 + 9x + 20
If a + b = 25 and a2 + b2 = 225, then find ab.
Verify the following:
(a + b)(a + b)(a + b) = a3 + 3a2b + 3ab2 + b3
