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प्रश्न
Two vertices of a \(\triangle \mathrm{ABC}\) are \(\mathrm{A}(-1,4)\) and \(\mathrm{B}(5, 2)\) and its centroid is (0, –3). The coordinates of C are ______.
विकल्प
(4, 3)
(4, 15)
(–4, –15)
(–15, –4)
MCQ
रिक्त स्थान भरें
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उत्तर
Two vertices of a \(\triangle \mathrm{ABC}\) are \(\mathrm{A}(-1,4)\) and \(\mathrm{B}(5, 2)\) and its centroid is (0, –3). The coordinates of C are (–4, –15).
Explanation:
Using \(\frac{-1 + 5 + x_C}{3} = 0\)
\(\Rightarrow x_C = -4\)
And \(\frac{4 + 2 + y_C}{3} = -3\)
\(\Rightarrow y_C = -15\)
Hence \(C(-4, -15)\).
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