हिंदी

Two vertices of a (\triangle \mathrm{ABC}) are (\mathrm{A}(–1,4)) and (\mathrm{B}(5, 2)) and its centroid is ((0, –3)). The coordinates of C are ______.

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प्रश्न

Two vertices of a \(\triangle \mathrm{ABC}\) are \(\mathrm{A}(-1,4)\) and \(\mathrm{B}(5, 2)\) and its centroid is (0, –3). The coordinates of C are ______.

विकल्प

  • (4, 3)

  • (4, 15)

  • (–4, –15)

  • (–15, –4)

MCQ
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उत्तर

Two vertices of a \(\triangle \mathrm{ABC}\) are \(\mathrm{A}(-1,4)\) and \(\mathrm{B}(5, 2)\) and its centroid is (0, –3). The coordinates of C are (–4, –15).

Explanation:

Using \(\frac{-1 + 5 + x_C}{3} = 0\)

\(\Rightarrow x_C = -4\)

And \(\frac{4 + 2 + y_C}{3} = -3\)

\(\Rightarrow y_C = -15\) 

Hence \(C(-4, -15)\).

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अध्याय 13: Section and Mid-point Formulae - COMPETENCY-FOCUSED QUESTIONS [पृष्ठ २१३]

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आर.एस. अग्रवाल Mathematics [English] Class 10 ICSE
अध्याय 13 Section and Mid-point Formulae
COMPETENCY-FOCUSED QUESTIONS | Q 23. | पृष्ठ २१३
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