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प्रश्न
Two numbers are in the ratio 4 : 7. If 4 is subtracted from each of the numbers, then the ratio becomes 7 : 13. Find the numbers.
योग
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उत्तर
Here, let the two numbers be:
4x and 7x (since they are in the ratio 4 : 7)
According to the given condition:
`(4x - 4)/(7x - 4) = 7/13`
Thus, cross-multiplying the above expression,
13(4x − 4) = 7(7x − 4)
52x − 52 = 49x − 28
52x − 49x = −28 + 52
3x = 24
∴ x = 8
Substituting, x = 8 in 4x and 7x, we get:
4x = 4(8) = 32
7x = 7(8) = 56
Hence, the numbers are 32 and 56.
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