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प्रश्न
Two bodies, A and B of equal mass are kept at heights 20 m and 30 m respectively. Calculate the ratio of their potential energies.
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उत्तर
Let the equal mass of two bodies A and B be m.
Given : height h1 = 20 m
and h2 = 30 m
Potential energy of body A = mgh1
= m × g × 20
Potential energy of body B = mgh2
= m × g × 30
`"Ratio""P"_1/"P"_2=("m"xx"g"xx20)/("m"xx"g"xx30)=2/3`
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| Group 'A' | Group 'B' | ||
| (1) | Rolling object | (a) | Heat energy |
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(e)
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