Advertisements
Advertisements
प्रश्न
Two angles of a polygon are right angles and the remaining are 120° each. Find the number of sides in it.
Advertisements
उत्तर
Let the number of sides = n
Sum of interior angles = (n - 2) × 180°
= 180n - 360°
Sum of 2 right angles = 2 × 90° = 180°
∴ Sum of other angles = 180n - 360° - 180°
= 180n - 540°
No.of vertices at which these angles are formed = n - 2
∴ Each interior angle = `(180"n" - 540)/("n" - 2)`
∴ `(180 "n" - 540)/("n" - 2) = 120°`
180n - 540 = 120n - 240
180n - 120n = - 240 + 540
60n = 300
n = `300/60`
n = 5
APPEARS IN
संबंधित प्रश्न
Calculate the sum of angle of a polygon with : 25 sides
Find the number of sides in a polygon if the sum of its interior angle is: 1620°
Find the number of sides in a polygon if the sum of its interior angle is: 32 right-angles.
Is it possible to have a polygon, whose sum of interior angle is: 4500°
In a hexagon ABCDEF, side AB is parallel to side FE and ∠B : ∠C : ∠D : ∠E = 6 : 4 : 2 : 3. Find ∠B and ∠D.
What is the formula for finding the sum of interior angles of a polygon with n sides?
What is the sum of interior angles of a triangle?
How many triangles are formed when all diagonals are drawn from one vertex of an octagon?
A polygon has an interior angle sum of 900°. How many sides does it have?
What is the sum of all interior angles of a hexagon?
