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प्रश्न
Triangles ABC and DEF are similar.
If area (ΔABC) = 16 cm, area (ΔDEF) = 25 cm2 and BC = 2.3 cm find EF.
योग
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उत्तर
We have
area (ΔABC) = 16cm2
area (ΔDEF) = 25 cm2
and BC = 2.3 cm
Since, `"area (ΔABC)"/"area (ΔDEF)" = "BC"^2/"EF"^2`
⇒ `(16)/(25) = (2.3)^2/"EF"^2`
⇒ `(2.3)/"EF" = (4)/(5)`
⇒ 4 EF = 5 x 2.3
⇒ EF = `(11.5)/(4)`
⇒ EF = 2.875 cm.
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