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प्रश्न
Answer the following question.
Three photodiodes D1, D2, and D3 are made of semiconductors having band gaps of 2.5 eV, 2 eV, and 3 eV respectively. Which of them will not be able to detect light of wavelength 600 nm?
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उत्तर
The energy of the incident light
`E = (hC)/lambda`
= `((6.6 xx 10^-34) xx (3 xx 10^8))/((600 xx 10^-9)(1.6 xx 10^-19))`
E = 2.06 eV
The incident radiations can be detected by a photodiode if the energy of incident radiation photon is greater than the band gap. This is true only for D2 (2 eV). Hence, only D2 will detect the light of 600 nm wavelength.
संबंधित प्रश्न
In the case of semiconductors, the valence and conduction bands ______.
ASSERTION (A): The electrical conductivity of a semiconductor increases on doping.
REASON (R): Doping always increases the number of electrons in the semiconductor.
What is the resistivity range for metals (conductors)?
Which band-gap range characterizes insulators?
How does the resistance of metals change as temperature increases?
How does the resistance of semiconductors change as temperature increases?
How many free electrons are available in semiconductors at room temperature?
What happens when even a tiny applied voltage is placed across a metal?
What are the valence-band and conduction-band occupancies in an insulator?
What is the approximate band gap of Diamond?
