Question

The zeros of the polynomial `x^2 + 1/6x - 2` are ______.

विकल्प

• –3, 4

• `(-3)/2, 4/3`

• `(-4)/3, 3/2`

• none of these

Answer 1

The zeros of the polynomial `x^2 + 1/6x - 2` are `underlinebb((-3)/2, 4/3)`.

Explanation:

`x^2 + 1/6x - 2 = (6x^2 + x - 12)/6`.

6x² + x – 12 = 6x² + 9x – 8x – 12

= 3x(2x + 3) – 4(2x + 3)

= (2x + 3)(3x – 4)

∴ The zeros are `(-3)/2` and `4/3`.