हिंदी

The weekly profit (in rupees) of 100 shops are distributed as follows: Profit per shop No. of shops 0 – 1000 10 1000 – 2000 16 2000 – 3000 26 3000 – 4000 20 4000 – 5000 20 5000 – 6000 5 6000 –7000 3 - Mathematics and Statistics

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प्रश्न

The weekly profit (in rupees) of 100 shops are distributed as follows:

Profit per shop No. of shops
0 – 1000 10
1000 – 2000 16
2000 – 3000 26
3000 – 4000 20
4000 – 5000 20
5000 – 6000 5
6000 – 7000 3

Find the limits of the profit of middle 60% of the shops.

योग
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उत्तर

To find the limits of the profit of middle 60% of the shops, we have to find P20 and P80.

We construct the less than cumulative frequency table as given below:

Profit per shop
(in rupees)
No. of shops
(f)
Less than Cumulative frequency 
(c.f.)
0 – 1000 10 10
1000 –  2000 16 26 ← P20
2000 –  3000 26 52
3000 – 4000 20 72
4000 –  5000 20 92 ← P80
5000 –  6000 5 97
6000 –  7000 3 100
Total 100  

Here, N = 100

P20 class = class containing `((20"N")/100)^"th"` observation

 ∴ `(20"N")/(100) = (20xx100)/(100)` = 20

Cumulative frequency which is just greater than (or equal to) 20 is 26.

∴ P20 lies in the class 1000 – 2000.
∴ L = 1000, f = 16, c.f. = 10, h = 1000

P20 = `"L"+"h"/"f"((20"N")/(100) - "c.f.")`

= `1000 + (1000)/(16)(20 - 10)`

 = `1000+125/2(10)`

= 1000 + 625
∴ P20 = 1625

P80 class = class containing `((80"N")/100)^"th"` observation

∴ `(80"N")/(100) = (80xx 100)/(100)` = 80

Cumulative frequency which is just greater than (or equal to) 80 is 92.

∴ P80 lies in the class 4000 – 5000
∴ L = 4000, f = 20, c.f. = 72, h = 1000

P80 = `"L"+"h"/"f"((80"N")/(100) - "c.f.")`

= `4000 + (1000)/(20)(80 - 72)`

= 4000 + 50(8)

= 4000 + 400
∴ P80 = 4400
∴ the profit of middle 60% of the shops lies between the limits 1,625 to 4,400.

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Relations Among Quartiles, Deciles and Percentiles
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अध्याय 1: Partition Values - Exercise 1.2 [पृष्ठ १६]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
अध्याय 1 Partition Values
Exercise 1.2 | Q 9 | पृष्ठ १६

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