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प्रश्न
The weekly profit (in rupees) of 100 shops are distributed as follows:
| Profit per shop | No. of shops |
| 0 – 1000 | 10 |
| 1000 – 2000 | 16 |
| 2000 – 3000 | 26 |
| 3000 – 4000 | 20 |
| 4000 – 5000 | 20 |
| 5000 – 6000 | 5 |
| 6000 – 7000 | 3 |
Find the limits of the profit of middle 60% of the shops.
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उत्तर
To find the limits of the profit of middle 60% of the shops, we have to find P20 and P80.
We construct the less than cumulative frequency table as given below:
| Profit per shop (in rupees) |
No. of shops (f) |
Less than Cumulative frequency (c.f.) |
| 0 – 1000 | 10 | 10 |
| 1000 – 2000 | 16 | 26 ← P20 |
| 2000 – 3000 | 26 | 52 |
| 3000 – 4000 | 20 | 72 |
| 4000 – 5000 | 20 | 92 ← P80 |
| 5000 – 6000 | 5 | 97 |
| 6000 – 7000 | 3 | 100 |
| Total | 100 |
Here, N = 100
P20 class = class containing `((20"N")/100)^"th"` observation
∴ `(20"N")/(100) = (20xx100)/(100)` = 20
Cumulative frequency which is just greater than (or equal to) 20 is 26.
∴ P20 lies in the class 1000 – 2000.
∴ L = 1000, f = 16, c.f. = 10, h = 1000
P20 = `"L"+"h"/"f"((20"N")/(100) - "c.f.")`
= `1000 + (1000)/(16)(20 - 10)`
= `1000+125/2(10)`
= 1000 + 625
∴ P20 = 1625
P80 class = class containing `((80"N")/100)^"th"` observation
∴ `(80"N")/(100) = (80xx 100)/(100)` = 80
Cumulative frequency which is just greater than (or equal to) 80 is 92.
∴ P80 lies in the class 4000 – 5000
∴ L = 4000, f = 20, c.f. = 72, h = 1000
P80 = `"L"+"h"/"f"((80"N")/(100) - "c.f.")`
= `4000 + (1000)/(20)(80 - 72)`
= 4000 + 50(8)
= 4000 + 400
∴ P80 = 4400
∴ the profit of middle 60% of the shops lies between the limits 1,625 to 4,400.
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