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प्रश्न
In a particular factory, workers produce various types of output units.
The following distribution was obtained.
| Output units Produced | No. of workers |
| 70 – 74 | 40 |
| 75 – 79 | 45 |
| 80 – 84 | 50 |
| 85 – 89 | 60 |
| 90 – 94 | 70 |
| 95 – 99 | 80 |
| 100 – 104 | 100 |
Find the percentage of workers who have produced less than 82 output units.
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उत्तर
Since the given data is not continuous, we have to convert it in the continuous form by subtracting 0.5 from the lower limit and adding 0.5 to the upper limit of every class interval.
∴ The class intervals will be 69.5 – 74.5, 74.5 – 79.5, etc.
We construct the less than cumulative frequency table as given below:
| Output units produced | No. of workers (f) |
Less than Cumulative frequency (c.f.) |
| 69.5 – 74.5 | 40 | 40 |
| 74.5 – 79.5 | 45 | 85 |
| 79.5 – 84.5 | 50 | 135 |
| 84.5 – 89.5 | 60 | 195 |
| 89.5 – 94.5 | 70 | 265 |
| 94.5 – 99.5 | 80 | 345 |
| 99.5 – 104.5 | 100 | 445 |
| Total | 445 |
Here, N = 445
Let Px = 82
The value 82 lies in the class 79.5 – 84.5.
∴ L = 79.5, f = 50, c.f. = 85, h = 5
∴ Px = `"L"+"h"/"f"(("xN")/100-"c.f.")`
∴ 82 = `79.5 + 5/50(("x"xx445)/100-85)`
∴ 82 − 79.5 = `1/10(4.45"x" - 85)`
∴ 2.5 × 10 = `4.45"x" - 85`
∴ 25 + 85 = 4.45x
∴ `110/4.45` = x
∴ x = `11000/445`
∴ x = `(2200)/89`
∴ x = 24.72
∴ 24.72% of workers produced less than 82 output units.
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