हिंदी

The volume of the given solid is:

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प्रश्न

The volume of the given solid is:

 The image displays a solid composite figure formed by a right circular cylinder of height $r$ and base radius $r$, surmounted by a right circular cone of height $r$ and attached to a hemisphere at the bottom.

विकल्प

  • \[\frac{4}{3} \pi r^{3}\]

  • \[\frac{4}{3} \pi r^{2}\]

  • \[2 \pi r^{3}\]

  • \[4 \pi r^{3}\]

MCQ
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उत्तर

\[\boldsymbol{2\pi r^{3}}\]

Explanation:

From figure,

Height of cone (h) = r

Height of cylinder (H) = r

Radius of hemispherical portion = Radius of cylindrical portion = Radius of conical portion = r.

From figure,

Volume of body = Volume of conical portion + Volume of cylindrical portion + Volume of hemispherical portion

\[{} = \frac{1}{3}\, \pi r^2 h + \pi r^2 H + \frac{2}{3}\, \pi r^3\]

\[{} = \frac{1}{3}\, \pi r^2 \cdot r + \pi r^2 \cdot r + \frac{2}{3}\, \pi r^3\]

\[{} = \frac{1}{3}\, \pi r^3 + \pi r^3 + \frac{2}{3}\, \pi r^3\]

\[{} = \frac{\pi r^3 + 3\pi r^3 + 2\pi r^3}{3}\]

\[{} = \frac{6\pi r^3}{3}\]

= 2πr3

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अध्याय 20: Cylinder, Cone and Sphere - EXERCISE 20 (F) [पृष्ठ ३२३]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 20 Cylinder, Cone and Sphere
EXERCISE 20 (F) | Q 1. (b) | पृष्ठ ३२३
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