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The value of the determinant ∣ ∣ ∣ ∣ ∣ a 2 a 1 cos n x cos ( n + 1 ) x cos ( n + 2 ) x sin n x sin ( n + 1 ) x sin ( n + 2 ) x ∣ ∣ ∣ ∣ ∣ is independent of (a) n (b) a (c) x (d) none of these

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प्रश्न

The value of the determinant

\[\begin{vmatrix}a^2 & a & 1 \\ \cos nx & \cos \left( n + 1 \right) x & \cos \left( n + 2 \right) x \\ \sin nx & \sin \left( n + 1 \right) x & \sin \left( n + 2 \right) x\end{vmatrix}\text{ is independent of}\]

 

विकल्प

  • n

  • a

  • x

  • none of these

MCQ
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उत्तर

(a) n
\[\text{ Let }A = nx, B = \left( n + 1 \right) x, C = \left( n + 2 \right) x\]
\[ \Rightarrow C - B = x, B - A = x, C - A = 2x\]
Thus, the given determinant is
\[ \begin{vmatrix} a^2 & a & 1\\\cos A & \cos B & \cos C\\\sin A & \sin B & \sin C \end{vmatrix}\]
\[ = a^2 \left( \cos B \sin C - \cos C \sin B \right) - a \times \left( \cos A \sin C - \cos C \sin A \right) + 1 \times \left( \cos A \sin B - \sin A \cos B \right)\]
\[ = a^2 \sin \left( C - B \right) - a \sin \left( C - A \right) + \sin \left( B - A \right)\]
\[ = a^2 \sin x - a \sin 2x + \sin x \left[\text{ Independent of n }\right]\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Determinants - Exercise 6.7 [पृष्ठ ९३]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 5 Determinants
Exercise 6.7 | Q 6 | पृष्ठ ९३

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