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The Sum of Three Consecutive Terms of an Ap is 21 and the Sum of the Squares of These Terms is 165. Find These Terms - Mathematics

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प्रश्न

The sum of three consecutive terms of an AP is 21 and the sum of the squares of these terms is 165. Find these terms

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उत्तर

Let the required terms be (a-d) , a and ( a+d) 

Then (a-d) + a+ (a+d) = 21

⇒ 3a = 21 

⇒ a =7 

Also , `(a - d)^2 + a^2 + (a + d)^2 = 165`

⇒ `3a^2 + 2d^2 = 165 `

⇒ `(3 xx 49 +2d^2) = 165`

⇒`2d^2 = 165 - 147 = 18`

⇒`d^2 = 9`

⇒ `d = +- 3`

Thus ,`a = 7 and d = +- 3`

Hence, the required terms are (4,7,10) or (10,7,4).

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अध्याय 11: Arithmetic Progression - Exercises 2

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 11 Arithmetic Progression
Exercises 2 | Q 9

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