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प्रश्न
The standard potential of the cell in the following reaction is ______.
\[\ce{Cd_{(s)} + Cu^{2+}_{(1M)} -> Cd^{2+}_{(1M)} + Cu_{(s)}}\]
`("E"_("Cd")^circ = - 0.403V, "E"_("Cu")^circ = 0.334V)`
विकल्प
– 0.737 V
0.737 V
– 0.069 V
0.069 V
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उत्तर
The standard potential of the cell in the following reaction is 0.737 V.
Explanation:
`"E"_"cell"^circ = "E"_"RHE"^circ - "E"_"LHE"^circ`
= 0.334 – (– 0.403 V)
= 0.737 V
APPEARS IN
संबंधित प्रश्न
Choose the most correct option.
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Answer the following in one or two sentences.
What is standard cell potential for the reaction
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Answer the following in brief.
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Calculate emf of the cell at 25°C.
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`E_(Zn)^0` = −0.76 V, `E_(Cr)^0` = −0.74 V
Answer the following:
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(E0 = −0.257 V)
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| Element | `"E"^0 ("V")` |
| Al | −1.66 |
| Fe | −0.44 |
| Hg | +0.79 |
| Cu | +0.337 |
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\[\ce{Ni_{(s)} | Ni^{2+}_{( aq)} || Au^{3+}_{( aq)} | Au_{(s)}}\]
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if \[\ce{E{^{\circ}_{Ni}}}\] = −0.25 V and \[\ce{E{^{\circ}_{Al}}}\] = −1.66 V?
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