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प्रश्न
The solution of `dy/dx` − y = 1, y(0) = 1 is given by ______.
विकल्प
y = −ex + 1
y = −e − x − 1
y = −1 + ex
y = 2eх − 1
MCQ
रिक्त स्थान भरें
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उत्तर
The solution of `dy/dx` − y = 1, y(0) = 1 is given by y = 2eх − 1.
Explanation:
The equation `dx/dy` − y = 1 is a linear differential equation. rearranging it as `dy/(1 + y) = dx` and integrating both sides gives:
In(1 + y) = x + C ⇒ 1 + y = Aex ⇒ y = 4ex − 1
Apply the Initial Condition:
using y(0) = 1, we substitute x = 0 and y = 1
1 = Ae0 − 1 ⇒ 1 = A − 1 ⇒ A ⇒ 2
Substituting back into the equation gives y = 2ex −1
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