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The slope of one of the straight lines ax2 + 2hxy + by2 = 0 is twice that of the other, show that 8h2 = 9ab

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प्रश्न

The slope of one of the straight lines ax2 + 2hxy + by2 = 0 is twice that of the other, show that 8h2 = 9ab

योग
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उत्तर

The equation of the given straight line is

ax2 + 2hxy + by2 = 0   .......(1)

Given that the slopes of the straight lines are m and 2m

∴ m + 2m = `- (2"h")/"b"`

(m)(2m) = `"a"/"b"`

3 m = `- (2"h")/"b"`

and 

2m2 = `"a"/"b"`

m = `- (2"h")/(3"b")`

⇒ `2( - (2"h")/(3"b"))^2 = "a"/"b"`

⇒ `2((4"h"^2)/(9"b"^2)) = "a"/"b"`

⇒ 8h2 = 9ab

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Pair of Straight Lines
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.4 [पृष्ठ २८२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.4 | Q 8 | पृष्ठ २८२

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