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प्रश्न
The slope of a line (6, k) and (1 − 3k, 3) is `1/2`. The value of k is ______.
विकल्प
−11
11
`-1/11`
`1/11`
MCQ
रिक्त स्थान भरें
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उत्तर
The slope of a line (6, k) and (1 − 3k, 3) is `1/2`. The value of k is −11.
Explanation:
Here,
Points: (6, k) and (1 − 3k, 3)
Slope (m): `1/2`
Using the slope formula:
`m = (y_2 - y_1)/(x_2 - x_1)`
`1/2 = (3 - k)/((1 - 3k) - 6)`
`1/2 = (3 - k)/(-3k - 5)`
Cross-multiply to solve for k:
1(− 3k − 5) = 2(3 − k)
−3k − 5 = 6 − 2k
−3k + 2k = 6 + 5
−k = 11
∴ k = −11
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