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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

The slant height of a frustum of a cone is 4 m and the perimeter of circular ends are 18 m and 16 m. Find the cost of painting its curved surface area at ₹ 100 per sq. m

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प्रश्न

The slant height of a frustum of a cone is 4 m and the perimeter of circular ends is 18 m and 16 m. Find the cost of painting its curved surface area at ₹ 100 per sq. m

योग
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उत्तर

Slant height of a frustum (l) = 4 m

Perimeter of the top part = 18 m

2πR = 18

`2 xx 22/7 xx "R"` = 18

R = `(18 xx 7)/(2 xx 22) xx 63/22`

Perimeter of the bottom = 16 m

2πr = 16

`2 xx 22/7 xx "r"` = 16

r = `(16 xx 7)/(2 xx 22) = 28/11`

C.S.A of the frustum = π l (R + r) sq.units

= `22/7 xx 4 (63/22 + 28/11)`

= `22/7 xx 4 ((63 + 56)/22)`

= `22/7 xx 4 xx 119/22`

= 4 × 17

= 68 sq.units

Cost of painting

= ₹ 100 × 68

= ₹ 6800

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अध्याय 7: Mensuration - Unit Exercise – 7 [पृष्ठ २९९]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 7 Mensuration
Unit Exercise – 7 | Q 7 | पृष्ठ २९९

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