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The reaction between X and Y is first order with respect to X and second order with respect to Y. If the concentration of X is halved and the concentration of Y is doubled the rate of reaction will be - Chemistry (Theory)

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प्रश्न

The reaction between X and Y is first order with respect to X and second order with respect to Y. If the concentration of X is halved and the concentration of Y is doubled the rate of reaction will be ______.

विकल्प

  • same as the initial value.

  • three times the initial value.

  • double the initial value.

  • half the initial value.

MCQ
रिक्त स्थान भरें
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उत्तर

The reaction between X and Y is first order with respect to X and second order with respect to Y. If the concentration of X is halved and the concentration of Y is doubled the rate of reaction will be double the initial value.

Explanation:

We are given:

Order with respect to X = 1

Order with respect to Y = 2

So the rate law is:

Rate = k[X]1[Y]2

Now, suppose initially 

[X] = x, [Y] = y

Then

Initial Rate = kxy2

Now the changes

[X] is halved → x/2

[Y] is doubled → 2y

∴ New rate = `k * x/2 * (2y)^2`

= `k * x/2 * 4y^2`

= 2kxy2

∴ New Rate = 2 × (Initial Rate)

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अध्याय 4: Chemical Kinetics - LONG ANSWER TYPE QUESTIONS [पृष्ठ २६५]

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अध्याय 4 Chemical Kinetics
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