Question

The ratio of the base area and the curved surface of a conical tent is 40: 41. If the height is 18 m, Find the air capacity of the tent in terms of n.

Answer 1

Given: `"base area"/"curved surface" = 40/41`

⇒ `(πr^2)/(πrsqrt(h^2 + r^2)) = 40/41`    ...( Where h is the height and r is the radius of conical tent)

⇒ `(r)/(sqrt(18^2 + r^2)) = 40/41`             ....( ∵ h = 18 m)

⇒ r = 80 m

∴ Air capacity = `1/3 π (80)^2 xx 18`

Air capacity = 38,400 π cu m.