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प्रश्न
The ratio of the 11th term to 17th term of an A.P. is 3 : 4. Find the ratio of 5th term to 21st term of the same A.P. Also, find the ratio of the sum of first 5 terms to that of first 21 terms.
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उत्तर
Given: The 11th term : 17th term = 3 : 4 for an A.P. Let first term = a and common difference = d.
Step-wise calculation:
1. Express the terms:
T11 = a + 10d
T17 = a + 16d
2. Use the given ratio:
(a + 10d) : (a + 16d) = 3 : 4
⇒ 4(a + 10d) = 3(a + 16d)
⇒ 4a + 40d = 3a + 48d
⇒ a = 8d
3. Ratio of 5th to 21st term:
T5 = a + 4d
T21 = a + 20d
Substitute a = 8d : T5 : T21
= (8d + 4d) : (8d + 20d)
= 12d : 28d
= 3 : 7
4. Ratio of sum of first 5 terms to first 21 terms:
`S_5 = 5/2 [2a + 4d]`
`S_21 = 21/2 [2a + 20d]`
So S5 : S21 = 5(2a + 4d) : 21(2a + 20d).
Substitute a = 8d (so 2a = 16d):
S5 : S21 = 5(16d + 4d) : 21(16d + 20d)
= 5 × 20d : 21 × 36d
= 100d : 756d
= 25 : 189
