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प्रश्न
The rate of formation of a dimer in a second order reaction is 7.5 × 10−3 mol L−1s−1 at 0.05 mol L−1 monomer concentration. Calculate the rate constant.
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उत्तर
Let us consider the dimerisation of a monomer M
\[\ce{2M -> (M)2}\]
Rate = k [M]n
Given that n = 2 and [M] = 0.05 mol L−1
Rate = 7.5 × 10−3 mol L−1s−1
k = `"Rate"/["M"]^"n"`
k = `(7.5 xx 10^-3)/((0.05)^2)`
k = 3 mol−1Ls−1
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