हिंदी

The product of first three terms of a G.P. is $$–1$$ and the common ratio is $$–\frac{3}{4}$$. The sum of these three terms is ______.

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प्रश्न

The product of first three terms of a G.P. is $$-1$$ and the common ratio is $$-\frac{3}{4}$$. The sum of these three terms is ______.

विकल्प

  • $$\frac{12}{13}$$

  • $$\frac{11}{13}$$

  • $$\frac{11}{12}$$

  • $$\frac{13}{12}$$

MCQ
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उत्तर

The product of first three terms of a G.P. is $$-1$$ and the common ratio is $$-\frac{3}{4}$$. The sum of these three terms is `underlinebb(13/12)`.

Explanation:

If the first term is $$a$$, then $$a^3(-3/4)^3=-1$$, giving $$a = \frac{4}{3}$$. The sum is $$a(1 + r + r^2) = \frac43\left(1-\frac34 + \frac9{16}\right) = \frac{13}{12}$$.

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अध्याय 11: Geometric Progression - COMPETENCY-FOCUSED QUESTIONS [पृष्ठ १८२]

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आर.एस. अग्रवाल Mathematics [English] Class 10 ICSE
अध्याय 11 Geometric Progression
COMPETENCY-FOCUSED QUESTIONS | Q 20. | पृष्ठ १८२
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