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प्रश्न
The product of first three terms of a G.P. is $$-1$$ and the common ratio is $$-\frac{3}{4}$$. The sum of these three terms is ______.
विकल्प
$$\frac{12}{13}$$
$$\frac{11}{13}$$
$$\frac{11}{12}$$
$$\frac{13}{12}$$
MCQ
रिक्त स्थान भरें
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उत्तर
The product of first three terms of a G.P. is $$-1$$ and the common ratio is $$-\frac{3}{4}$$. The sum of these three terms is `underlinebb(13/12)`.
Explanation:
If the first term is $$a$$, then $$a^3(-3/4)^3=-1$$, giving $$a = \frac{4}{3}$$. The sum is $$a(1 + r + r^2) = \frac43\left(1-\frac34 + \frac9{16}\right) = \frac{13}{12}$$.
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