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प्रश्न
The perimeter of a rectangle is 32 cm and its length is 6 cm. Find the area of the rectangle.
योग
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उत्तर
Given: Perimeter P = 32 cm, Length l = 6 cm.
Step-wise calculation:
1. Perimeter of a rectangle:
P = 2(l + w)
2. Substitute P = 32 and l = 6:
32 = 2(6 + w)
3. Divide by 2:
16 = 6 + w
4. Solve for width:
w = 16 – 6
= 10 cm
5. Area:
A = l × w
= 6 × 10
= 60 cm2
The area of the rectangle is 60 cm2.
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