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प्रश्न
The next term of the A.P. $$\sqrt{3}, \sqrt{12}, \sqrt{27}, \sqrt{48}, ......$$ is ______.
विकल्प
$$\sqrt{72}$$
$$\sqrt{68}$$
$$\sqrt{75}$$
$$\sqrt{56}$$
MCQ
रिक्त स्थान भरें
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उत्तर
The next term of the A.P. $$\sqrt{3}, \sqrt{12}, \sqrt{27}, \sqrt{48}, ......$$ is `underlinebb(sqrt(75))`.
Explanation:
The terms are $$\sqrt{3}, 2\sqrt{3}, 3\sqrt{3}, 4\sqrt{3}$$, so the next term is $$5\sqrt{3} = \sqrt{75}$$.
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