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प्रश्न
The nature of roots of the quadratic equation 9x2 – 6x – 2 = 0 is ______.
विकल्प
No real roots
2 equal real roots
2 distinct real roots
More than 2 real roots
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उत्तर
The nature of roots of the quadratic equation 9x2 – 6x – 2 = 0 is 2 distinct real roots.
Explanation:
The given quadratic equation:
9x2 – 6x – 2 = 0
Here, a = 9, b = –6 and c = –2
∴ Discriminant, D = b2 – 4ac
= (–6)2 – 4(9)(–2)
= 36 – 36(–2)
= 36 – (–72)
= 36 + 72
= 108
∵ D = 108 > 0, the roots are real and unequal.
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Solution :
Compare x2 + 2x – 9 = 0 with ax2 + bx + c = 0
a = 1, b = 2, c = `square`
∴ b2 – 4ac = (2)2 – 4 × `square` × `square`
Δ = 4 + `square` = 40
∴ b2 – 4ac > 0
∴ The roots of the equation are real and unequal.
