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प्रश्न
The mean of numbers in A.P. 2, 4, 6, 8, …, 40 is ______.
विकल्प
`(40+2)/2`
`20/2(2+40)`
`10/2(2+40)`
840
MCQ
रिक्त स्थान भरें
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उत्तर
The mean of numbers in A.P. 2, 4, 6, 8, …, 40 is `bbunderline((40+2)/2)`.
Explanation:
Given,
A.P. = 2, 4, 6, 8, ……, 40
First term (a) = 2
Common difference (d) = 4 − 2 = 2
Last term (l) = 40
Let no. of terms in A.P. be n.
⇒ 40 = a + (n − 1)d
⇒ 40 = 2 + 2(n − 1)
⇒ 40 = 2 + 2n − 2
⇒ 2n = 40
⇒ n = `40/2` = 20.
By formula,
Sum of first n terms of an A.P. = `n/2(a + l) = 20/2(2 + 40) = 420`
Mean = `"Sum of observations"/"No. of observations" = 420/20` = 21
Solving,
⇒ `(40+2)/2 = 42/2 = 21`
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