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The mean and S.D. of the scores of 100 candidates were found to be 80 and 15 respectively. Later, it was discovered that a score of 50 was wrongly read as 40. The correct mean

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प्रश्न

The mean and S.D. of the scores of 100 candidates were found to be 80 and 15 respectively. Later, it was discovered that a score of 50 was wrongly read as 40. The correct mean and S.D. respectively are ______ 

विकल्प

  • 14.76, 80.1

  • 80.1, 14.76

  • 80.1, 217.99

  • 217.99, 80.1

MCQ
रिक्त स्थान भरें
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उत्तर

The mean and S.D. of the scores of 100 candidates were found to be 80 and 15 respectively. Later, it was discovered that a score of 50 was wrongly read as 40. The correct mean and S.D. respectively are 80.1, 14.76.

Explanation:

Corrected ∑x = 80 × 100 - 40 + 50 = 8010

∴ Corrected = `overlinex = 8010/100 = 80.1`

Incorrect ∑x2 

= `n[sigma^2 + overlinex^2] = 100[15^2 + 80^2] = 662500`

Corrected ∑x2

= 662500 - 1600 + 2500

= 663400

∴ Corrected `sigma = sqrt(663400/100 - (80.10)^2) = 14.76`

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Standard Deviation
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